p404

LeetCode p404 Sum of Left Leaves 题解

1.题目:

Find the sum of all left leaves in a given binary tree.

Example:

3

/
9 20
/
15 7

There are two left leaves in the binary tree, with values 9 and 15 respectively. Return 24.

题意:

输入一个二叉树,输出所有左节点的累加和。

2.解题思路:

这里的左节点指左右节点都为空的左节点。

3.代码


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* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class {
public int sumOfLeftLeaves(TreeNode root) {
if (root == null)
return 0;
if (root.left == null)
return sumOfLeftLeaves(root.right);
if (root.left.left == null && root.left.right == null)
return root.left.val + sumOfLeftLeaves(root.right);
return sumOfLeftLeaves(root.left) + sumOfLeftLeaves(root.right);
}
}

4.一些总结: