leetcode解题-path sum


描述

Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and sum = 22,
5
/
4 8
/ /
11 13 4
/
7 2 1
return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.

分析

深度优先遍历可解,时间O(n),空间O(logn)

代码

Python

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class (object):
def hasPathSum(self, root, sum):
"""
:type root: TreeNode
:type sum: int
:rtype: bool
"""

if not root:
return False
if not root.left and not root.right:
return root.val == sum

return self.hasPathSum(root.left, sum - root.val) or
self.hasPathSum(root.right, sum - root.val)