a1002题解

int () {
   double P[100010][2] = {0};
  int m;
  double e, c;
    for(int i = 0; i < 2; i++) {
        scanf("%d", &m);
       for(int j = 0; j < m; j++) {
            scanf("%lf%lf", &e, &c);
           P[(int)e][0] = e;
           P[(int)e][1] = P[(int)e][1] + c;
       } 
   }
    int maxn = 0;
   for(int i = 0; i < 10010; i++) {
        if(P[i][1] != 0) {
          maxn++;
      }
    }
    printf("%d", maxn);
    for(int i = 1010; i >= 0; i--) {
        if(P[i][1] != 0) {
          printf(" %d %.1lf", (int)P[i][0], P[i][1]);
       }
    }   
 return 0;
}