palindrome (manacher)

链接

A - Palindrome

题意

输出最长的子回文串的长度

题解

马拉车模板题

代码

1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
#include <vector>
#include <iostream>
#include <string>
using namespace std;
int Manacher(string s) {
// Insert '#'
string t = "$#";
for (int i = 0; i < s.size(); ++i) {
t += s[i];
t += "#";
}
// Process t
vector<int> p(t.size(), 0);
int mx = 0, id = 0, resLen = 0, resCenter = 0;
for (int i = 1; i < t.size(); ++i) {
p[i] = mx > i ? min(p[2 * id - i], mx - i) : 1;
while (t[i + p[i]] == t[i - p[i]]) ++p[i];
if (mx < i + p[i]) {
mx = i + p[i];
id = i;
}
if (resLen < p[i]) {
resLen = p[i];
resCenter = i;
}
}
return resLen - 1;
}
int main() {
string s1;
int k=0;
while(1)
{
k++;
cin>>s1;
if(s1[0]=='E')
break;
else
{
cout<<"Case "<<k<<": "<<Manacher(s1)<<endl;
}
}
return 0;
}