【leetcode】46. permutations

1.题目描述

Given a collection of distinct integers, return all possible permutations.

给定一个没有重复数字的序列,返回其所有可能的全排列。

Example:

Input: [1,2,3]
Output:
[
[1,2,3],
[1,3,2],
[2,1,3],
[2,3,1],
[3,1,2],
[3,2,1]
]

2.Solutions

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public static List<List<Integer>> permute(int[] nums) {
List<List<Integer>> list = new ArrayList<>();

backtrack(list, new ArrayList<Integer>(), nums);
return list;
}

private static void (List<List<Integer>> list, List<Integer> tempList,
int[] nums) {
//打印中间结果,便于理解。
printList(tempList);
if (tempList.size() == nums.length) {
list.add(new ArrayList<>(tempList));
} else {
for (int i = 0; i < nums.length; i++) {
if (tempList.contains(nums[i]))
continue; // element already exists, skip
tempList.add(nums[i]);
backtrack(list, tempList, nums);
tempList.remove(tempList.size() - 1);
}
}
}

private static void printList(List<Integer> list) {
if (list.size() == 0){
return;
}
for (Integer integer : list) {
System.out.print(integer);
}
System.out.println();
}

(完)