对角遍历


Question

给定一个二叉树,打印每个具有负斜率()的对角线的所有节点。假设节点的左,右子与父节点成45度角。

     1
   /  
  2    3
 /   / 
4  5 6   7
    /     
   8       9

输出:
1 3 7 9
2 5 6
4 8



Code

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import java.util.HashMap;
import java.util.Map.Entry;
import java.util.Vector;

public class A053
{
static class TreeNode{
int data;
TreeNode left;
TreeNode right;
TreeNode(int data)
{
this.data=data;
left = null;
right =null;
}
}
static void diagonalPrintUtil(TreeNode root,int d,
HashMap<Integer,Vector<Integer>> diagonalPrint){
if (root == null)
return;
Vector<Integer> k = diagonalPrint.get(d);
if (k == null)
{
k = new Vector<>();
k.add(root.data);
}
else
{
k.add(root.data);
}
diagonalPrint.put(d,k);
diagonalPrintUtil(root.left, d + 1, diagonalPrint);
diagonalPrintUtil(root.right, d, diagonalPrint);
}
static void diagonalPrint(TreeNode root)
{
HashMap<Integer,Vector<Integer>> diagonalPrint = new HashMap<>();
diagonalPrintUtil(root, 0, diagonalPrint);

//System.out.println("Diagonal Traversal of Binnary Tree");

for (Entry<Integer, Vector<Integer>> entry : diagonalPrint.entrySet())
{
//Spliterator<Integer> a = entry.getValue().spliterator();
//System.out.println(entry.getValue());
//System.out.println(entry.getValue().size());
for(int i=0;i<entry.getValue().size();i++) {
System.out.print(entry.getValue().get(i)+" ");
}
System.out.println();
}
}
public static void main(String[] args) {
TreeNode root = new TreeNode(1);
root.left = new TreeNode(2);
root.right = new TreeNode(3);
root.left.left = new TreeNode(4);
root.left.right = new TreeNode(5);
root.right.left = new TreeNode(6);
root.right.right = new TreeNode(7);
root.right.left.left = new TreeNode(8);
root.right.right.right = new TreeNode(9);
diagonalPrint(root);
}
}