【leetcode14】longest common prefix 最长公共前缀

“The Linux philosophy is “Laugh in the face of danger”.Oops.Wrong One. “Do it yourself”. Yes, that”s it.”
Linux的哲学就是“在危险面前放声大笑”,呵呵,不是这句,应该是“一切靠自己,自力更生”才对。

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* 编写一个函数来查找字符串数组中的最长公共前缀。
* <p>
* 如果不存在公共前缀,返回空字符串 ""。
* <p>
* 示例 1:
* <p>
* 输入: ["flower","flow","flight"]
* 输出: "fl"
* 示例 2:
* <p>
* 输入: ["dog","racecar","car"]
* 输出: ""
* 解释: 输入不存在公共前缀。
*/
public class {
public String longestCommonPrefix (String[] strs) {
if (strs.length == 0)
return "";
if (strs.length == 1)
return strs[0];
int length = strs[0].length() < strs[1].length() ? strs[0].length() : strs[1].length();
StringBuilder prefix = new StringBuilder();
for (int i = 0; i <length;++i){
if(strs[0].charAt(i) == strs[1].charAt(i))
prefix.append(strs[0].charAt(i));
else
break;
}
if(prefix.length() == 0)
return "";
for(int i=2;i<strs.length;++i){
int l = prefix.length()<strs[i].length()?prefix.length():strs[i].length();
for(int j=0;j<l;++j){
if(prefix.charAt(j)!=strs[i].charAt(j)) {
prefix = prefix.delete(j, prefix.length());
break;
}
}
if(prefix.length()>strs[i].length())
prefix = new StringBuilder(strs[i]);

}
return prefix.toString();
}
}