分析:这道题是真的弱智 12345678 def (S): res = S.split() for i,s in enumerate(res): if s[0] in 'aeiouAEIOU': res[i] = s + 'ma' + 'a'*(i+1) else: res[i] = s[1:]+s[0] + 'ma' + 'a'*(i+1) return ' '.join(res) 赞微海报分享
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