python闰年

def r(n):
    if n%4 == 0 and n%100 != 0 or n%400 == 0:
        return True
    else:
        return False

def t(y,m,d):
    m1 = [31,28,31,30,31,30,31,31,31,30,31]
    m2 = [31,29,31,30,31,30,31,31,31,30,31]
    if r(y):
        days = sum(m2[:m-1]) + d
    else:
        days = sum(m1[:m-1]) + d
    return days

def per():
    n = input('输入年月日，如20180402：') or '20180402'
    y = int(n[:4])
    m = int(n[4:6])
    d = int(n[6:])
    return y, m, d

while True:
    y, m, d = per()
    days = t(y, m, d)
    print('%d年%d月%d日，是%d年的第%d天nn'%(y,m,d,y,days))