对称二叉树101

题目:给定一个二叉树,检查它是否是镜像对称的。

输入:

1
2
3
4
5
    1
/
2 2
/ /
3 4 4 3

输出:True

思路:递归

代码:

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class :
def __init__(self, x):
self.val = x
self.left = None
self.right = None

class Solution:
def helper(self,left,right):

if not left and not right:
return True
if not left or not right:
return False
# 递归过程
if left.val == right.val:
return self.helper(left.left, right.right) and self.helper(left.right, right.left)
else:
return False

def isSymmetric(self, root):
"""
:type root: TreeNode
:rtype: bool
"""
if not root:
return True
else:
return self.helper(root.left, root.right)

# 例子
tree = TreeNode(1)
left_tree = TreeNode(2)
left_tree.left = TreeNode(3)
left_tree.right = TreeNode(4)
right_tree = TreeNode(2)
right_tree.left = TreeNode(4)
right_tree.right = TreeNode(3)
print(Solution().isSymmetric(tree))