删除链表中重复元素

题目:删除链表中重复元素

输入:1->2->3->3->4->4->5

输出:1->2->5

思路:两个指针,pre和cur,看前后两个指针的val是否相同

注:运用虚拟头节点

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class :
def deleteDuplicates(self, head):
"""
:type head: ListNode
:rtype: ListNode
"""
if head == None or head.next == None:
return head

dummy = ListNode(0)
dummy.next = head
pre = dummy
cur = dummy.next

while cur != None:
while cur.next and cur.next.val == pre.next.val:
cur = cur.next
if pre.next == cur:
pre = pre.next
else:
pre.next = cur.next
cur = cur.next
return dummy.next

例子

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ll = creat_ll([1,2,3,3,3,3,4,4,5])
res = Solution().deleteDuplicates(ll)
print_ll(res)