经典面试题之线程按顺序交替打印

  • 编写一个程序,开启 3 个线程,这三个线程的 ID 分别为 A、B、C,每个线程将自己的 ID 在屏幕上打印 10 遍,要求输出的结果必须按顺序显示。
  • 如:ABCABCABC…… 依次递归
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public class  {

public static void main(String[] args) {
AlternateDemo ad = new AlternateDemo();
new Thread(new Runnable() {

public void run() {
for (int i = 1; i <= 20; i++) {
ad.loopA(i);
}
}
}, "A").start();

new Thread(new Runnable() {

public void run() {

for (int i = 1; i <= 20; i++) {
ad.loopB(i);
}
}
}, "B").start();

new Thread(new Runnable() {

public void run() {

for (int i = 1; i <= 20; i++) {
ad.loopC(i);
System.out.println("-----------------------------------");
}

}
}, "C").start();
}

}

class AlternateDemo{

private int number = 1;

private Lock lock = new ReentrantLock();
private Condition condition1 = lock.newCondition();
private Condition condition2 = lock.newCondition();
private Condition condition3 = lock.newCondition();

/**
* @param totalLoop : 循环第几轮
*/
public void loopA(int totalLoop){
lock.lock();

try {
//1. 判断
if(number != 1){
condition1.await();
}

//2. 打印
for (int i = 1; i <= 1; i++) {
System.out.println(Thread.currentThread().getName() + "t" + i + "t" + totalLoop);
}

//3. 唤醒
number = 2;
condition2.signal();
} catch (Exception e) {
e.printStackTrace();
} finally {
lock.unlock();
}
}

public void loopB(int totalLoop){
lock.lock();

try {
//1. 判断
if(number != 2){
condition2.await();
}

//2. 打印
for (int i = 1; i <= 1; i++) {
System.out.println(Thread.currentThread().getName() + "t" + i + "t" + totalLoop);
}

//3. 唤醒
number = 3;
condition3.signal();
} catch (Exception e) {
e.printStackTrace();
} finally {
lock.unlock();
}
}

public void loopC(int totalLoop){
lock.lock();

try {
//1. 判断
if(number != 3){
condition3.await();
}

//2. 打印
for (int i = 1; i <= 1; i++) {
System.out.println(Thread.currentThread().getName() + "t" + i + "t" + totalLoop);
}

//3. 唤醒
number = 1;
condition1.signal();
} catch (Exception e) {
e.printStackTrace();
} finally {
lock.unlock();
}
}

}