全排列(可能含重复数字)

Given a collection of numbers that might contain duplicates, return all possible unique permutations.

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class  {
public List<List<Integer>> permuteUnique(int[] nums) {
List<List<Integer>> list=new ArrayList<>();
Arrays.sort(nums);
backTrack(list,new ArrayList<>(),nums,new boolean [nums.length]);
return list;
}

public void backTrack(List<List<Integer>> list,List<Integer> tempList,int [] nums,boolean[] used)
{
if(tempList.size()==nums.length)
{
list.add(new ArrayList<>(tempList));
}
else
{
for(int i=0;i<nums.length;i++)
{
if(used[i]||(i>0)&&(nums[i]==nums[i-1])&&(!used[i-1])) continue;
used[i]=true;
tempList.add(nums[i]);
backTrack(list,tempList,nums,used);
used[i]=false;
tempList.remove(tempList.size()-1);
}
}
}
}