Third Maximum Number
Given a non-empty array of integers, return the third maximum number in this array. If it does not exist, return the maximum number. The time complexity must be in O(n).
Example 1:
Input: [3, 2, 1]
Output: 1
Explanation: The third maximum is 1.
Example 2:
Input: [1, 2]
Output: 2
Explanation: The third maximum does not exist, so the maximum (2) is returned instead.
Example 3:
Input: [2, 2, 3, 1]
Output: 1
Explanation: Note that the third maximum here means the third maximum distinct number.
Both numbers with value 2 are both considered as second maximum.
代码一(8 ms):
public class Solution {
public int thirdMax(int[] nums) {
Arrays.sort(nums);
int t = 0;
int lc = 0;
for (int i = nums.length - 1; i >= 0; i--) {
if (i == nums.length - 1) {
t = nums[i];
} else {
if (t > nums[i]) {
t = nums[i];
lc += 1;
}
}
if (lc >= 2) {
break;
}
}
if (lc >= 2) {
return t;
}
return nums[nums.length - 1];
}
}
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