decode ways

dp的题目,1.确定维数, 2.dp[i]所代表的含义, 3. dp[i]和之前值的关系

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class (object):
def numDecodings(self, s):
"""
:type s: str
:rtype: int
"""
if not s:
return 0
if s[0] == "0":
return 0
if len(s) == 1:
return 1
dp = [0 for _ in range(len(s))]
# obviously, dp[0] = 1
dp[0] = 1
if "1" <= s[:2] <= "26" and s[1] != "0":
dp[1] = 2
elif s[1] == "0" and s[0] not in "12":
return 0
else:
dp[1] = 1
for i in range(2, len(s)):
if s[i] == "0" and s[i-1] not in "12":
return 0
elif s[i] == "0":
dp[i] = dp[i-2]
elif "11" <= s[i-1:i+1] <= "26":
dp[i] = dp[i-1] + dp[i-2]
else:
dp[i] = dp[i-1]
return dp[-1]