spiral matrix ii

虽然code不是那么优美,或者在代码上还有优化的地方,毕竟是完全靠自己写的,再简洁的答案,如果不是自己亲手写的,效果并不大。而且这题显然也没有什么时间空间好优化的地方。

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class (object):
def generateMatrix(self, n):
"""
:type n: int
:rtype: List[List[int]]
"""
if n == 0:
return []
res = [[0 for _ in range(n)] for _ in range(n)]
tr = lc = 0
br = rc = n - 1
num = 1
while num <= n**2:
if num <= n**2:
# top
for i in range(lc, rc+1):
res[tr][i] = num
num += 1
tr += 1
if num <= n**2:
# right
for i in range(tr, br+1):
res[i][rc] = num
num += 1
rc -= 1
if num <= n**2:
# bot
for i in range(rc, lc-1, -1):
res[br][i] = num
num += 1
br -= 1
if num <= n**2:
# left
for i in range(br, tr-1, -1):
res[i][lc] = num
num += 1
lc += 1
return res