leetcode 95 不同的二叉搜索树 ii

给定一个整数 n,生成所有由 1 … n 为节点所组成的二叉搜索树。

示例:

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输入: 3
输出:
[
[1,null,3,2],
[3,2,null,1],
[3,1,null,null,2],
[2,1,3],
[1,null,2,null,3]
]
解释:
以上的输出对应以下 5 种不同结构的二叉搜索树:

1 3 3 2 1
/ / /
3 2 1 1 3 2
/ /
2 1 2 3

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# class TreeNode(object):
# def __init__(self, x):
# self.val = x
# self.left = None
# self.right = None

class (object):
def generateTrees(self, n):
"""
:type n: int
:rtype: List[TreeNode]
"""

def helper(l):
if not l:
return [None]
elif len(l) == 1:
return [TreeNode(l[0])]
ans = []
for i, n in enumerate(l):
for left in helper(l[:i]):
for right in helper(l[i+1:]):
root = TreeNode(n)
if left is not None:
root.left = left
if right is not None:
root.right = right
ans.append(root)
return ans

if n <= 0:
return []

return helper([i for i in range(1, n+1)])