leetcode longestincreasingsubsequence

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import java.util.Arrays;
import java.util.HashMap;

public class {

* Given an unsorted array of integers, find the length of longest increasing subsequence.
*
* Example:
*
* Input: [10,9,2,5,3,7,101,18]
* Output: 4
* Explanation: The longest increasing subsequence is [2,3,7,101], therefore the length is 4.
* Note:
*
* There may be more than one LIS combination, it is only necessary for you to return the length.
* Your algorithm should run in O(n2) complexity.
* Follow up: Could you improve it to O(n log n) time complexity?
*
* @param nums
* @return
*/
public int lengthOfLIS(int[] nums) {

HashMap<Integer, Integer> m = new HashMap<>();

int n = nums.length;
int[] dp = new int[n];
Arrays.fill(dp, Integer.MAX_VALUE);
int t = 0;

for (int i = 0; i < n; i++) {
int idx = binarySearch(dp, 0, i, nums[i]);
dp[idx] = nums[i];
if (idx == t) {
t++;
}
}
return t;
}


public int binarySearch(int[] nums, int left, int right, int target){
while(left <= right){
int mid = left + ((right - left) >> 1);
if (nums[mid] == target) return mid;
else if (nums[mid] > target) left = mid -1;
else right = mid + 1;
}
return left;
}
}