leetcode 135 candy

There are N children standing in a line. Each child is assigned a rating value.

You are giving candies to these children subjected to the following requirements:

  • Each child must have at least one candy.
  • Children with a higher rating get more candies than their neighbors.

What is the minimum candies you must give?

Example 1:

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Input: [1,0,2]
Output: 5
Explanation: You can allocate to the first, second and third child with 2, 1, 2 candies respectively.

Example 2:

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Input: [1,2,2]
Output: 4
Explanation: You can allocate to the first, second and third child with 1, 2, 1 candies respectively.
The third child gets 1 candy because it satisfies the above two conditions.

  • 用一个数组保存每一个小孩的candies数目,并初始化为1。
  • 从前往后遍历rantings,如果当前比之前一个大,candies[i] = candies[i-1]+1
  • 从后往前遍历rantings,如果当前比他前面的一个小,candies[i-1] = max(candies[i-1], candies[i]+1)
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class  {
public int candy(int[] ratings) {
if (ratings.length == 0) return 0;
int n = 0;
int[] candies = new int[ratings.length];
for(int i=0; i<ratings.length; i++) {
candies[i] = 1;
}
for (int i=1; i<ratings.length; i++) {
if(ratings[i] > ratings[i-1]) {
candies[i] = candies[i-1]+1;
}
}
for (int i=ratings.length-1; i>0; i--) {
if(ratings[i-1] > ratings[i]){
candies[i-1] = Math.max(candies[i-1], candies[i]+1);
}
}

for (int i: candies){
n+= i;
}
return n;
}
}