leetcode 73 set matrix zeros

Given a m x n matrix, if an element is 0, set its entire row and column to 0. Do it in place.

Follow up:

Did you use extra space?
A straight forward solution using O(mn) space is probably a bad idea.
A simple improvement uses O(m + n) space, but still not the best solution.
Could you devise a constant space solution?


1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
class  {
public void setZeroes(int[][] matrix) {
if(matrix == null || matrix.length == 0) return ;
boolean firstRow = false;
boolean firstCol = false;

for(int i=0; i<matrix.length; i++){
for(int j=0; j<matrix[0].length; j++){
if(matrix[i][j] == 0){
if(i == 0) firstRow = true;
if(j == 0) firstCol = true;

matrix[0][j] = 0;
matrix[i][0] = 0;
}
}
}
for(int i=1; i<matrix.length; i++){
for(int j=1; j<matrix[0].length; j++){
if(matrix[i][0] == 0 || matrix[0][j] == 0){
matrix[i][j] = 0;
}
}
}

if(firstRow){
for(int i=0; i<matrix[0].length; i++){
matrix[0][i] = 0;
}
}
if(firstCol){
for(int i=0; i<matrix.length; i++){
matrix[i][0] = 0;
}
}
return ;
}
}
  • 如果matrix[i][j] == 0, 则将第i行的第一个元素和第j列的第一个元素置0
  • 扫描第一行和第一列,将对应的行和列置0
  • 注意第一行和第一列需要特殊处理。