动态规划

dp[][0]代表这个节点可以压缩(儿子节点不来)反之相反。

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#include<cstdio>
#include<iostream>
#include<algorithm>
#include<vector>
#define N 6001
using namespace std;
vector<int> g[N];
int dp[N][2], root, flag[N];
void (int x)
{
for (int i = 0; i < g[x].size();i++)
{
int son=g[x][i];
dfs(son);
dp[x][1] = max(max(dp[x][1], dp[x][1] + dp[son][0]), dp[son][0]);
dp[x][0] = max(max(dp[x][0], dp[x][0] + dp[son][1]), max(dp[son][1], dp[son][0]));
}
}
int main()
{
int n;
cin >> n;
for (int i = 1; i <= n;i++)
{
cin >> dp[i][1];
}
for (int i = 1; i <= n;i++)
{
int a, b;
cin>>a>>b;
g[b].push_back(a);
flag[a] = 1;
}
for (int i = 1; i <= n;i++)
{
if(!flag[i])
{
root = i;
break;
}
}
dfs(root);
cout << max(dp[root][0], dp[root][1]) << endl;
}