hdu 2063 过山车

二分图问题用网络流跑

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/* problem: HDU2063
* Auther:CaiCai
* 第二次用EK跑二分图,没什么好说的,建好图就一定可以做
* 建图就是女生一边,男生一边,再把源点和束点找到,权值分别是1这样就可以把图建完了。
*/
#include <iostream>
#include <cstdio>
#include <cmath>
#include <string>
#include <cstring>
#include <algorithm>
#include <limits>
#include <vector>
#include <stack>
#include <queue>
#include <set>
#include <map>
#define lowbit(x) ( x&(-x) )
#define pi 3.141592653589793
#define e 2.718281828459045
using namespace std;
typedef long long ll;
const int INF=0x3f3f3f3f;
const int maxN=505;
int m, n;
int temp;
int r[maxN<<1][maxN<<1], flow[maxN<<1], pre[maxN<<1];
int sum1 = 0;
int sum2 = 0;
int K, M, N;
int tot;
int bfs(int st,int en)
{
queue<int> q;
while(!q.empty())
q.pop();
memset(pre, -1, sizeof pre);
pre[0] = 0;
flow[0]=INF;
q.push(0);
while(!q.empty())
{
int u = q.front();
q.pop();
for (int i = 1; i <= tot;i++)
{
if(r[u][i]>0&&pre[i]==-1)
{
pre[i] = u;
flow[i] = min(flow[u], r[u][i]);
q.push(i);
}
}
}
return pre[en] == -1 ? -1 : flow[en];
}
int maxflow(int st,int en)
{
int icr = 0;
int ans = 0;
while((icr=bfs(st,en))!=-1)
{
int k = en;
while(k!=st)
{
int last = pre[k];
r[last][k] -= icr;
r[k][last] += icr;
k = last;
}
ans += icr;
}
return ans;
}
int main()
{
while (~scanf("%d",&K))
{
if(K==0)
break;
scanf("%d%d",&M,&N);
memset(r, 0, sizeof r);
tot = M + N+1;
for (int i = 1; i <= M;i++) r[0][i] = 1;
for (int i = M + 1; i <= M + N;i++) r[i][tot] = 1;
for (int i = 0; i < K; i++)
{
int a, b;
scanf("%d", &a);
scanf("%d", &b);
r[a][b + M] = 1;
}
int ans = maxflow(0, tot);
printf("%dn", ans);
}

}