a1082 read number in chinese

Given an integer with no more than 9 digits, you are supposed to read it in the traditional Chinese way. Output Fu first if it is negative. For example, -123456789 is read as Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu. Note: zero (ling) must be handled correctly according to the Chinese tradition. For example, 100800 is yi Shi Wan ling ba Bai.

Each input file contains one test case, which gives an integer with no more than 9 digits.

For each test case, print in a line the Chinese way of reading the number. The characters are separated by a space and there must be no extra space at the end of the line.

-123456789 

Fu yi Yi er Qian san Bai si Shi wu Wan liu Qian qi Bai ba Shi jiu 

100800 

yi Shi Wan ling ba Bai

#include <bits/stdc++.h>
using namespace std;

char num[10][5] = {"ling", "yi", "er", "san", "si", "wu", "liu", "qi", "ba", "jiu"};
char wei[5][5] = {"Shi", "Bai", "Qian", "Wan", "Yi"};

int main()
{
    char str[11];
    cin.getline(str, 11);
    int length = strlen(str);
    int left = 0, right = length - 1; 
    if (str[0] == '-')
    {
        printf("Fu");
        left++;
    }

    while (left + 4 <= right) //right每次左移4位,直到left与right在同一节
        right -= 4;

    while (left < length) //每次处理数字的一节
    {
        bool flag = false;
        bool isPrint = false;
        while (left <= right) //从左至右处理某节的每一位
        {
            if (left > 0 && str[left] == '0') //当前位为0
                flag = true;
            else
            {
                if (flag)
                {
                    printf(" ling");
                    flag = false;
                }
                //只要不是首位,后面的每一位都输出空格
                if (left > 0)
                    printf(" ");
                printf("%s", num[str[left] - '0']); //输出当前位数字
                isPrint = true;                        //该节至少一位输出
                if (left != right)
                {
                    printf(" %s", wei[right - left - 1]);
                }
            }
            left++;
        }
        if (isPrint == true && right != length - 1)
        {
            printf(" %s", wei[(length - 1 - right) / 4 + 2]);
        }
        right += 4;
    }
    return 0;
}