1065 A+B and C (64bit)
Given three integers A, B and C in [−2^63,2^63], you are supposed to tell whether A+B>C.
Input Specification:
The first line of the input gives the positive number of test cases, T (≤10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.
Output Specification:
For each test case, output in one line Case #X: true
if A+B>C, or Case #X: false
otherwise, where X is the case number (starting from 1).
Sample Input:
3
1 2 3
2 3 4
9223372036854775807 -9223372036854775808 0
Sample Output:
Case #1: false
Case #2: true
Case #3: false
解答
#include <bits/stdc++.h>
int main()
{
int T, count = 1;
scanf("%d", &T);
long long A, B, C, result;
while (T--)
{
scanf("%lld%lld%lld", &A, &B, &C);
result = A + B;
bool flag;
if (A > 0 && B > 0 && result < 0)
flag = true;
//负溢出
else if (A < 0 && B < 0 && result >= 0)
flag = false;
//没有溢出
else if (result > C)
flag = true;
else
flag = false;
if (flag == true)
printf("Case #%d: truen", count++);
else
printf("Case #%d: falsen", count++);
}
return 0;
}
近期评论