
题目来源:https://leetcode.com/problems/path-sum/
代码:
/**
- Definition for a binary tree node.
- public class TreeNode {
- int val;
- TreeNode left;
- TreeNode right;
- TreeNode(int x) { val = x; }
- }
*/
class Solution {
public boolean hasPathSum(TreeNode root, int sum) {int s = 0; return dfs(root,sum,s);}
public boolean dfs(TreeNode root, int sum,int s){if(root == null){ return false; } if(root.left == null && root.right == null){ //到达叶节点,判断和是否等于sum s += root.val; if(s == sum){ return true; } } s += root.val; //递归 boolean left = dfs(root.left,sum,s); boolean right = dfs(root.right,sum,s); if(left||right){ return true; } return false;}
}




近期评论