1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 32 33 34 35 36 37 38 39 40 41 42 43 44 45 46 47 48 49 50 51 52 53 54 55 56 57 58 59 60 61 62 63 64 65 66 67 68 69 70 71 72 73 74 75 76 77 78 79 80 81 82 83 84 85 86
|
using namespace std; #define forl(i, l, r) for (int i = l; i <= r; i++) #define forr(i, r, l) for (int i = r; i >= l; i--) #define for1(i, n) for (int i = 1; i <= n; i++) #define fro1(i, n) for (int i = 1; i <= n; i++) #define for0(i, n) for (int i = 0; i < n; i++) #define fro0(i, n) for (int i = 0; i < n; i++) #define meminf(a) memset(a, inf, sizeof(a)) #define mem_1(a) memset(a, -1, sizeof(a)) #define mem0(a) memset(a, 0, sizeof(a)) #define memcp(a,b) memcpy(a,b,sizeof(b)) #define oper(type) bool operator <(const type y)const #define mp make_pair #define pu_b push_back #define pu_f push_front #define po_b pop_back #define po_f pop_front #define fi first #define se second #define whiel while #define retrun return typedef pair<long long, long long> pll; typedef vector<long long> vll; typedef pair<int, int> pii; typedef unsigned long long ull; typedef vector<int> vii; typedef long double db; typedef long long ll; typedef int itn; int (int &a,int &b,int &c,int &d){return scanf("%d%d%d%d",&a,&b,&c,&d);} int (int &a,int &b,int &c){return scanf("%d%d%d",&a,&b,&c);} int (int &a,int &b){return scanf("%d%d",&a,&b);} int (ll &a){return scanf("%lld",&a);} int (int &a){return scanf("%d",&a);} int in(char *s){return scanf("%s",s);} int in(char &s){return scanf("%c",&s);} int in(db &a){return scanf("%Lf",&a);} void out(int a){printf("%d ",a);} void outln(int a){printf("%dn",a);} void out(ll a){printf("%lld ",a);} void outln(ll a){printf("%lldn",a);} const db pi = acos((db)-1); const ll inf =0x3f3f3f3f; const db eps = 1e-8; const int N = 2.1e5; const ll mod = 1e9+7; int sign(db a) { return a < -eps ? -1 : a > eps;} int db_cmp(db a, db b){ return sign(a-b); } int a[N]; unordered_set<int>s; int main() { int q,n; in(q); while(q--){ in(n); for0(i,n){ in(a[i]); s.insert(a[i]); } sort(a,a+n); n=unique(a,a+n)-a; int maxx=a[n-1]; int tmp=maxx; if(maxx%2==0&&maxx%3==0&&maxx%5==0&&s.count(maxx/2)&&s.count(maxx/3)&&s.count(maxx/5)){ maxx=maxx/30*31; } for(int i=n-2;i>=0;i--){ if(tmp%a[i]){ for(int j=i-1;j>=0;j--){ if(tmp%a[j]&&a[i]%a[j]){ tmp+=a[j]; break; } } tmp+=a[i]; break; } } outln(max(maxx,tmp)); s.clear(); } return 0; }
|
近期评论