
Two Steps
- Describe possible outcomes
- Describe beliefs about likelihood of outcomes
Sample Space
Sample space is the set of all outcomes of the experiment. It can be discrete or continuous, finite or infinite.
Event: subset of sample space
Probability Axioms and Derived Consequences
Axioms:
- Nonnegativity: $P(A)ge0$
- Normalization: $P(Omega)=1$
- (Finite) additivity: if $Acap B=phi$, then $P(Acup B)=P(A)+P(B)$
Consequences:
- $P(A)le 1$
- $P(phi)=0$
- $P(A)+P(A^{C})=1$
- For mutually disjoint sets $A_1,A_2,ldots,A_k$,
$P(A_1cup A_2cupldotscup A_k)=P(A_1)+P(A_2)+ldots+P(A_k)$ - $P(s_1,s_2,ldots,s_k)=P(lbrace s_1rbrace)+P(lbrace s_2rbrace)+ldots+P(lbrace s_krbrace)$
- If $Asubset B$, $P(A)le P(B)$
- $P(Acup B)=P(A)+P(B)-P(Acap B)$
- $P(Acup B)le P(A)+P(B)$
- $P(Acup Bcup C)=P(A)+P(Bcap A^{C})+P(Ccap B^{C} cap A^{C})$
Probability Calculation
Four Steps
- Specify the sample sapce
- Specify a probability law
- Identify an event of interest
- Calculate
Discrete and Finite
- Two rolls of a tetrahedral die. X for the points of the first roll. Y for the points of the second roll. Sample Space:

- Discrete uniform probability law: every outcome has the same probability $frac{1}{16}$.
- $P(X=1)=4timesfrac{1}{16}=frac{1}{4}$
Let $Z=min(X,Y)$ - $P(Z=4)=frac{1}{16}$
- $P(Z=2)=5timesfrac{1}{16}=frac{5}{16}$
- $P(X=1)=4timesfrac{1}{16}=frac{1}{4}$
Continuous
- $(x,y)$ such that $0le x,yle 1$.
Sample space:
- Uniform probability law: Probability = Area
- $P(lbrace(x,y)|x+yle1/2rbrace)=frac{1}{2}timesfrac{1}{2}timesfrac{1}{2}=frac{1}{8}$
Discrete and Infinite
- Tossing a coin, record the number of times until its head faces up.
Sample space: $lbrace 1,2,ldotsrbrace$
Probability:
- $P(n)=frac{1}{2^{n}}$
$P(text{outcome is even})=P(2)+P(4)+ldots=frac{1}{4}frac{1}{1-frac{1}{4}}=frac{1}{3}$
Countable additivity axiom
If $A_1,A_2,ldots$ is an infinite sequence of disjoint events, then $P(A_1cup A_2cupldots)=sum P(A_i)$. It is this axiom that supports the calculation in Discrete and Infinite section. If it is not countable, consider the section Continuous and try to calculate $P(Omega)$
$$
P(Omega)=P(lbrace (x,y)|0le x,yle 1rbrace)=sum P((x,y))=sum 0=0.
$$
which is impossible.
Intepretations of probability theory
- (Narrow) a branch of math: Axioms $Rightarrow$ Theorems
- (Objective) Probability = Frequencies in infinite number of experiments
- (Subjective) Beliefs or Preferences
Role of probability theory
- A systematic way of analyzing phenomena with uncertain outcomes
- Whether the probability is useful for making predictions and decisions or not is related to whether the model fits the reality well or not.
- Statistics is to use data from real world to come up with good models for probability theory.
Relation:




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