
Free Energy vs. Renormalize Paramaters
p-wave
cal
delta^p(vec{q}, z) =& mathrm{Arg}left[ frac{Mk_{n^2}}{2}frac{1}{R}
left(
frac{1}{4pi}cdot frac{2R}{k_n^2 v}
+ tilde{z}cdotfrac{1}{4pi}
+ frac{2 R}{M k_n^2}Pi_r(vec{q},z)
right)
right] \
=& mathrm{Arg}left[
frac{1}{4pi}cdot frac{2R}{k_n^2 v}
+ tilde{z}cdotfrac{1}{4pi}
+ frac{2 R}{M k_n^2}Pi_r(vec{q},z + mathrm{i}0^+)
right]
end{align}
其中 (tilde{z}=z/E_n) , (E_n = k_n^2/(2M)) , (k_n^3 = 6pi^2n) , (n =
N/V)
begin{align}
frac{2 R}{M k_n^2}Pi_r(vec{q},z) =& (k_n R)cdotPi_r cdot frac{2}{Mk_n^3}\
=& tilde{R}left[
frac{2}{Mk_n^3}left( -frac{M}{V} right)sum_{vec{k}}1
- tilde{z}E_n frac{M^2}{V}frac{2}{Mk_n^3}sum_{vec{k}}frac{1}{k^2}
+ frac{2}{Mk_n^3}Pi^{l=1}(vec{q},z)
right] \
=& tilde{R}left[
-frac{1}{pi^2}int mathrm{d}tilde{k}cdot tilde{k}^2
-tilde{z} frac{1}{2pi^2}int mathrm{d}tilde{k}
+tilde{Pi}^{l=1}
right]
end{align}
其中 (tilde{R} = k_nR) , (tilde{k} = k/k_n)
begin{align}
tilde{Pi}^{l=1} = &frac{2}{Mk_n^3}Pi^{l=1}(vec{q},omega) \
=& frac{2}{Mk_n^3}frac{1}{V}frac{V}{(2pi)^3}int mathrm{d}tilde{k}
left[
k^2 cdot 4pi |Y_{lm}(hat{k})|^2
frac{1+n(xi_{vec{k}+vec{q}/2}) + n(xi_{-vec{k}+vec{q}/2})}
{xi_{vec{k}+vec{q}/2} + xi_{-vec{k}+vec{q}/2} - omega}
right] \
=& frac{2}{pi^2}int mathrm{d}tilde{k}cdottilde{k}^4left[
frac{1+n(xi_{vec{k}+vec{q}/2}) + n(xi_{-vec{k}+vec{q}/2})}
{tilde{xi}_{vec{k}+vec{q}/2} + tilde{xi}_{-vec{k}+vec{q}/2} - tilde{omega}}
right]
end{align}
其中 (tilde{xi} = xi/E_n) , (tilde{omega} = omega/E_n) , (n(xi)
= frac{1}{e^{beta xi}-1})
最终
begin{align}
frac{tilde{Omega}}{N E_n} =& frac{1}{N E_n}
frac{V}{(2pi^3)}int mathrm{d}^3vec{q}
cdot int frac{mathrm{d}omega}{pi}cdot frac{1}{e^{betaomega}-1} delta^p \
=& frac{3}{pi} int mathrm{d}tilde{q}cdot tilde{q}^2
int_{-infty}^{+infty}mathrm{d}tilde{omega}
cdot frac{1}{e^{tilde{beta}tilde{omega}}-1} tilde{delta}^p(vec{q},z)
end{align}
其中 (tilde{beta} = beta E_n) . 得自由能
begin{align}
frac{F}{NE_n} = frac{tilde{Omega}}{N E_n} -frac{mu}{E_n}
end{align}
即
begin{align}
f(tilde{mu}, tilde{R}) = tilde{Omega}'(tilde{mu}, tilde{R})-tilde{mu}
end{align}
其中 (tilde{mu} = mu/E_n).
(mu) 由
begin{align}
N = - frac{partialOmega}{partial mu}
end{align}
决定.
以 (varepsilon) 为单位
若以某一能量 (varepsilon) 为单位, 对应的长度单位 (k_{varepsilon} =
sqrt{2Mvarepsilon}) , 密度单位 (n_{varepsilon} =
k_{varepsilon}^3/(6pi^2)) , 那么
begin{align}
frac{Omega}{N varepsilon} = & frac{n_{varepsilon}}{n}int
mathrm{d}tilde{q}cdot tilde{q}^2
int_{-infty}^{+infty}mathrm{d}tilde{omega}
cdotfrac{3}{pi}cdot frac{1}{e^{tilde{beta}tilde{omega}}-1}
tilde{delta}^p(vec{q},z) \
= & frac{n_{varepsilon}}{n}int
mathrm{d}tilde{q}cdot tilde{q}^2
int_{-infty}^{+infty}mathrm{d}tilde{omega}
cdot f(tilde{q}, tilde{omega}, tilde{mu}, tilde{beta})
end{align}
其中
begin{align}
f(tilde{q}, tilde{omega}, tilde{mu}, tilde{beta}) =
frac{3}{pi}cdot frac{1}{e^{tilde{beta}tilde{omega}}-1}
tilde{delta}^p(vec{q},z)
end{align}
而
begin{align}
frac{n}{n_{varepsilon}} =& - frac{1}{n_{varepsilon}V}
frac{partialOmega}{partialmu}
=- frac{1}{n_{varepsilon}V}
frac{partialOmega/mu}{partialtilde{mu}}\
=& - frac{1}{n_{varepsilon}V}
frac{partial}{partialtilde{mu}}left[
V n_{varepsilon} int
mathrm{d}tilde{q}cdot tilde{q}^2
int_{-infty}^{+infty}mathrm{d}tilde{omega}
cdot f(tilde{q}, tilde{omega}, tilde{mu}, tilde{beta})
right] \
=& - frac{partial}{partialtilde{mu}}left[
int mathrm{d}tilde{q}cdot tilde{q}^2
int_{-infty}^{+infty}mathrm{d}tilde{omega}
cdot f(tilde{q}, tilde{omega}, tilde{mu}, tilde{beta})
right]
end{align}
所以最终要求的为
begin{align}
frac{Delta F}{NE_n} =& frac{Omega}{NE_n} + frac{mu}{E_n} \
=&frac{Omega}{Nvarepsilon}left( frac{varepsilon}{E_n} right)
+ tilde{mu} left( frac{varepsilon}{E_n} right) \
=& left( frac{n_{varepsilon}}{n} right)^{5/3}
intmathrm{d}tilde{q}cdot tilde{q}^2
int_{-infty}^{+infty}mathrm{d}tilde{omega}
cdot f(tilde{q}, tilde{omega}, tilde{mu}, tilde{beta})
+ tilde{mu} left( frac{n_{varepsilon}}{n} right)^{2/3} \
end{align}
横坐标为
begin{align}
frac{2R}{k_n^2v} = frac{2R}{k_{varepsilon v}}cdot
left( frac{n_{varepsilon}}{n} right)^{2/3}
end{align}
result
code
计算 (Delta F)
from matplotlib import pyplot as plt |
计算 (T_{C})
N = 100 |
def tm(omega, q, rkv, mu): |




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