maximumsubarray key solution perfect

Maximum Subarray

Easy

Given an integer array nums, find the contiguous subarray (containing at least one number) which has the largest sum and return its sum.

Example:

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> Input: [-2,1,-3,4,-1,2,1,-5,4],
> Output: 6
> Explanation: [4,-1,2,1] has the largest sum = 6.
>

Follow up:

If you have figured out the O(n) solution, try coding another solution using the divide and conquer approach, which is more subtle.

key

我们定义一个和为第一位数,然后用curSum来保存递增量

ps ans–>answer cur–>cursor

solution

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class  {
public int maxSubArray(int[] nums) {
int ans=nums[0], curSum=0;

for (int i=0; i<nums.length; i++) {
curSum = curSum + nums[i];
ans = Math.max(ans, curSum);
curSum = Math.max(0, curSum);
}

return ans;
}
}

perfect

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class  {
public int maxSubArray(int[] nums) {
int dp = nums[0], maxSum=nums[0];
for (int i=1; i<nums.length; i++) {
dp = dp<0?nums[i]:nums[i]+dp;
maxSum=Math.max(maxSum, dp);
}
return maxSum;
}
}