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树的后序遍历 posOrder

admin 11月 13, 2020 0 

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private static class BinaryNode<AnyType>
{
    BinaryNode(AnyType theElement)
    {
        this(theElement, null, null);
    }

    BinaryNode(AnyType theElement, BinaryNode<AnyType> lt, BinaryNode<AnyType> rt)
    {
        element = theElement;
        left = lt;
        right = rt;
    }

    AnyType element;
    BinaryNode<AnyType> left;
    BinaryNode<AnyType> right;
}

private BinaryNode<AnyType> root;

posOrder

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public void (BinaryNode<AnyType> Node)
    {
        if (Node != null)
        {
            posOrder(Node.left);
            posOrder(Node.right);
            System.out.print(Node.element + " ");
        }
    }
 
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public void posOrder(BinaryNode<AnyType> Node)
{
    Stack<BinaryNode> stack1 = new Stack<>();
    Stack<Integer> stack2 = new Stack<>();
    int i = 1;
    while(Node != null || !stack1.empty())
    {
        while (Node != null)
        {
            stack1.push(Node);
            stack2.push(0);
            Node = Node.left;
        }

        while(!stack1.empty() && stack2.peek() == i)
        {
            stack2.pop();
            System.out.print(stack1.pop().element + "   ");
        }

        if(!stack1.empty())
        {
            stack2.pop();
            stack2.push(1);
            Node = stack1.peek();
            Node = Node.right;
        }
    }
}
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