leetcode_reverse linked list

Reverse Linked List

Reverse a singly linked list.
(翻转链表)

Note:
A linked list can be reversed either iteratively or recursively. Could you implement both?

Example:

1. 迭代法

构建一个头结点,在遍历链表的过程中不断地采用头插法即可翻转链表。具体实现过程如下:

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# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None

class :
def reverseList(self, head: ListNode) -> ListNode:
new_head = ListNode(0)

p = head
while p:
tmp = p.next
p.next = new_head.next
new_head.next = p
p = tmp

return new_head.next

2. 递归法

递归的翻转后面的字符串,然后将当前的头结点放在最尾部,具体实现过程如下:

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# class ListNode:
# def __init__(self, x):
# self.val = x
# self.next = None

class :
def reverseList(self, head: ListNode) -> ListNode:
if not head or not head.next:
return head

new_head = self.reverseList(head.next)
head.next.next = head
head.next = None

return new_head