61. rotate list

explanation

  1. 算出length, k = k % len
  2. tail 连到head
  3. 找到新tail, tail.next = null
  4. return 新head

code

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* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class {
public ListNode rotateRight(ListNode head, int k) {
if (head == null) {
return null;
}
// get length, k = k%len, len - k -> null, final node->n0
int len = 1;
ListNode curt = head;
while (curt.next != null) {
len++;
curt = curt.next;
}
curt.next = head;

k = k % len;
// 断开tail, return head
ListNode tail = head;
int count = len - k;
for (int i = 1; i < count; i++) {
tail = tail.next;
}
head = tail.next;
tail.next = null;

return head;

}

}