458. last position of target

  1. Don’t discard Target
  2. Decrease the target range in each step

code

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public class  {
public int lastPosition(int[] nums, int target) {

if (nums == null || nums.length == 0) {
return -1;
}
int start = 0, end = nums.length - 1;
while (start + 1 < end) {
int mid = start + (end - start) / 2; // avoid out of range
if (nums[mid] == target) { // answer on the right part
start = mid;
} else if (nums[mid] < target) { // answer on the right part
start = mid;// mid + 1
} else {
end = mid; // mid - 1
}
}
if (nums[end] == target) {
return end;
} else if (nums[start] == target) {
return start;
} else {
return -1;
}


}
}

complexity

time: O(log(n))
space: O(1)