
2. Add Two Numbers
给你两个表示两个非负数字的链表。数字以相反的顺序存储,其节点包含单个数字。将这两个数字相加并将其作为一个链表返回。
Example:
Input: (2 -> 4 -> 3) + (5 -> 6 -> 4)
Output: 7 -> 0 -> 8
Explanation: 342 + 465 = 807.
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) { val = x; }
* }
*/
class Solution {
public ListNode addTwoNumbers(ListNode l1, ListNode l2) {
int sum =0;
ListNode p = new ListNode(0);
ListNode head=p;
while(l1 != null || l2 != null || sum!=0){
if (l1 != null) {
sum += l1.val;
l1 = l1.next;
}
if (l2 != null) {
sum += l2.val;
l2 = l2.next;
}
p.next = new ListNode(sum%10);
sum /= 10;
p = p.next;
}
return head.next;
}
}




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