ord() 和chr(), unichr()相反 ord('A') : ‘A ‘ —> 65 ord(u'u2020') : return 8224 chr(65) : 65 —> A ASCII code for ‘A’ is 65, ‘a’ is 97 1234567891011 ord('A')65ord('a')97chr(65)'A'chr(97)'a' Note: if {A:1, B:2, ….} ord('A')-64 注意最开始A为65,如果设定A为1,则 - 64 赞微海报分享
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