771. Jewels and Stones 题目链接 解题思路:无 code: 1234567 class Solution: def numJewelsInStones(self, J: str, S: str) -> int: c = 0 for i in S: if i in J: c = c + 1 return c 今天困了,简单刷一道题就睡了 赞微海报分享
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