merge sort for linked lists

  • splitList: fast/slow pointer method -> ⚠️ fast = head->next solve the odd/even sum of the list.
  • sortedMerge: the end of the recursion.
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struct Node
int val;
Node* next;
Node(int x):val(x),next(NULL){}
};

void splitList(Node* head, Node** front, Node** back){
Node *fast, *slow;
slow = head;
fast = head->next;

while(fast != NULL){
fast = fast->next;
if(fast != NULL){
fast = fast->next;
slow = slow->next;
}
}
*front = head;
*back = slow->next;
slow->next = NULL;
}

Node* sortedMerge(Node* a, Node* b){
if(a == NULL)
return b;
if(b == NULL)
return a;
Node* mergedNode;
if(a->val <= b->val){
mergedNode = new Node(a->val);
mergedNode->next = sortedMerge(a->next, b);
}else {
mergedNode = new Node(b->val);
mergedNode->next = sortedMerge(a, b->next);
}
return mergedNode;
}

void mergeSort(Node** headRef){
Node* head = *headRef;
Node* a;
Node* b;

if(head == NULL || head->next == NULL)
return;

splitList(head, &a, &b);
mergeSort(&a);
mergeSort(&b);

*headRef = sortedMerge(a, b);
}