剑指offe

Problem

输入某二叉树的前序遍历和中序遍历的结果,请重建出该二叉树。假设输入的前序遍历和中序遍历的结果中都不含重复的数字。例如输入前序遍历序列{1,2,4,7,3,5,6,8}和中序遍历序列{4,7,2,1,5,3,8,6},则重建二叉树并返回。

Solution

常规思路

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class 
{
public:
TreeNode* reConstructBinaryTree(vector<int> pre,vector<int> vin)
{
if (vin.size() <= 0 || pre.size() <= 0)
{
return NULL;
}

TreeNode* root = new TreeNode(pre[0]);

vector<int> leftPre, leftVin, rightPre, rightVin;

bool isRootLeft = true;

for (int i = 0; i < vin.size(); ++i)
{
if(vin[i] == pre[0])
{
isRootLeft = false;
continue;
}

if(isRootLeft)
{
leftVin.push_back(vin[i]);
leftPre.push_back(pre[i+1]);
}
else
{
rightVin.push_back(vin[i]);
rightPre.push_back(pre[i]);
}
}

root->left = reConstructBinaryTree(leftPre, leftVin);
root->right = reConstructBinaryTree(rightPre, rightVin);

return root;
}
};