
Problem
Given an array nums of n integers and an integer target, find three integers in nums such that the sum is closest to target. Return the sum of the three integers. You may assume that each input would have exactly one solution.
Example
Given array nums = [-1, 2, 1, -4], and target = 1.
The sum that is closest to the target is 2. (-1 + 2 + 1 = 2).
Python solution
import sys
class Solution:
def threeSumClosest(self, nums, target):
"""
:type nums: List[int]
:type target: ints
:rtype: int
"""
result, diff = 0, sys.maxsize
nums.sort()
for i in range(len(nums) - 2):
if i > 0 and nums[i] == nums[i - 1]:
continue
left, right = i + 1, len(nums) - 1
while left < right:
total = nums[i] + nums[left] + nums[right]
hold_diff = abs (total - target)
if not hold_diff:
return total
if hold_diff < diff:
result = total
diff = hold_diff
if total < target:
left += 1
else:
right -= 1
return result
if __name__ == "__main__":
sys.stdout.write("Input array: n")
nums = list(map(int, str(sys.stdin.readline()).strip().split()))
sys.stdout.write("Input target: n")
target = int(str(sys.stdin.readline()).strip())
sys.stdout.write("Result is: n" + str(Solution().threeSumClosest(nums, target)))




近期评论