日期与(某年)天数的相互转换

日期与(某年)天数的相互转换

源代码

int (int list[],int mon,int day)
{
    for(mon;mon>0;--mon)
        day+=list[mon-1];
        return day;
}

void switch_2(int list[],int day)
{
        int i,mon;
    for(i=0;i<13;++i){
        day-=list[i];
        if(day<=list[i+1]){
            mon=i+1;
            break; 
        }
    } 
    printf("%d月%d日",mon,day);   
} 

void main()
{
    int choice;
    printf("which cases do you want?n1.日期转换成天数n2.指定年份的天数求日期n");
    scanf("%d",&choice);
    int year,day,mon;//初始化年月日
    //输入年份 
    while(1){
        printf("inter a yearn");
        scanf("%d",&year);
        if(year>0)
            break;
    }
    //判断闰年 
    int a; 
    if((year%4==0&&year%100!=0)||year%400==0)
        a=29;
    else
        a=28;
    int list[] = {0,31,a,31,30,31,30,31,31,30,31,30,31};
    //输入月份
    if(choice==1) {
        while(1){
            printf("inter a monthn");
                scanf("%d",&mon);
                if(mon>0&&mon<=12)
                    break;
        }
    }
    //输入天数 
    while(1){
    printf("inter a dayn");
    scanf("%d",&day);
    if(day>0)
        break;
    } 
    if(choice==1){
        int D = switch_1(list,mon,day);//函数调用
        printf("%d年第%d天n",year,D);
    }

    else
        switch_2(list,day);//函数调用 
}









效果演示

 






			
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