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int main() { int a,k,sum,i,j,p[N]; char c[N]; char *b[10]={"ling","yi","er","san","si","wu","liu","qi","ba","jiu"}; sum=0; gets(c); for(k=0;c[k]>0;k++) { a=(c[k]-'0')%10; sum=sum+a; c[k]=(c[k]-'0')/10; } for(i=0;sum>0;i++) { p[i]=sum%10; sum=sum/10; } for(i=i-1;i>0;i--) { j=p[i]; printf("%s ",b[j]); }
printf("%s",b[p[0]]); return 0; }
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