c – 3 – max – min

max()
        1 返回容器中元素最大值
        2 def max(iterable, *, default, key):
        3 max(iterable, *[, default=obj, key=func]) -> value
        4 max(arg1, arg2, *args, *[, key=func]) -> value

min()
        1 返回容器中元素最小值
        2 def min(iterable, *, default, key):
        3 min(iterable, *[, default=obj, key=func]) -> value
        4 min(arg1, arg2, *args, *[, key=func]) -> value