1. two sum

Easy

https://leetcode.com/problems/two-sum/

Given an array of integers, return indices of the two numbers such that they add up to a specific target.

You may assume that each input would have exactly one solution, and you may not use the same element twice.

Example:

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Given nums = [2, 7, 11, 15], target = 9,

Because nums[0] + nums[1] = 2 + 7 = 9,
return [0, 1].

方法:

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class (object):
def twoSum(self, nums, target):
"""
:type nums: List[int]
:type target: int
:rtype: List[int]
"""
d = {}
for i in range(len(nums)):
d[nums[i]] = i
for i in range(len(nums)):
if target-nums[i] in d and d[target-nums[i]]!=i:
return [i, d[target-nums[i]]]
return

类似题目:

3Sum

4Sum

Two Sum II - Input array is sorted

Two Sum III - Data structure design

Two Sum IV - Input is a BST

Two Sum Less Than K