pat甲级1107

1107 Social Clusters (30 point(s))

原地址

思路:

  1. 并查集的应用,这里从把节点存到hobby数组,然后对hobby数组进行并查操作。

代码:

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using namespace std;
const int maxn = 1000+5;
const int INF = 0x3f3f3f3f;
const double eps = 1e-6;
const int MOD = 1e9+7;
const int sqrN = 316;
typedef long long ll;
#define pb push_back
#define pp pop_back
#define lowbit(x) ((x)&(-x))
#define mst(a,b) memset(a,b,sizeof(a))

int pre[maxn],hobby[maxn],res[maxn];
void () {
for (int i = 1; i <= maxn; ++i) pre[i] = i;
}
int find(int x) {
if (x == pre[x]) return x;
else {
int r = find(pre[x]);
pre[x] = r;
return r;
}
}
void Union(int a,int b) {
int Ra = find(a);
int Rb = find(b);
if (Ra != Rb) pre[Ra] = Rb;
}

int main() {
#ifdef ONLIGE_JUDGE
#else
freopen("H:\in.txt","r",stdin);
#endif
makeSet();
int n,t,cnt = 0;
scanf("%d",&n);
for (int i = 1, k; i <= n; ++i) {
scanf("%d:",&k);
for (int j = 1; j <= k; ++j) {
scanf("%d",&t);
if (!hobby[t]) hobby[t] = i; //如果在i喜欢之前没人喜欢,则喜欢t的人为i.
Union(i,find(hobby[t])); //将当前喜欢t的人与之前喜欢t的融入一个圈子
}
}
for (int i = 1; i <= n; ++i) {
res[find(i)]++;
}
for (int i = 1; i <= n; ++i) {
if (res[i]) cnt++;
}
cout << cnt << endl;
sort(res+1,res+n+1,greater<int>()); // res从1开始
for (int i = 1; i <= cnt; ++i)
printf("%d%c",res[i],i==cnt ? 'n' : ' ');
return 0;
}