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1.查询“某1”课程比“某2”课程成绩高的所有学生的学号; SELECT a.sid FROM (SELECT sid,score FROM SC WHERE cid=1) a,(SELECT sid,score FROM SC WHERE cid=3) b WHERE a.score>b.score AND a.sid=b.sid; 此题知识点,嵌套查询和给查出来的表起别名
2.查询平均成绩大于60分的同学的学号和平均成绩; SELECT sid,avg(score) FROM sc GROUP BY sid having avg(score) >60; 此题知识点,GROUP BY 语句用于结合合计函数,根据一个或多个列对结果集进行分组。group by后面不能接where,having代替了where
3.查询所有同学的学号、姓名、选课数、总成绩 SELECT Student.sid,Student.Sname,count(SC.cid),sum(score)FROM Student left Outer JOIN SC on Student.sid=SC.cid GROUP BY Student.sid,Sname
4.查询姓“李”的老师的个数; select count(teacher.tid)from teacher where teacher.tname like'李%'
5.查询没学过“叶平”老师课的同学的学号、姓名; SELECT Student.sid,Student.Sname FROM Student WHERE sid not in (SELECT distinct( SC.sid) FROM SC,Course,Teacher WHERE SC.cid=Course.cid AND Teacher.id=Course.tid AND Teacher.Tname='叶平'); 此题知识点,distinct是去重的作用
6.查询学过“···”并且也学过编号“···”课程的同学的学号、姓名; select a.SID,a.SNAME from (select student.SNAME,student.SID from student,course,sc where cname='c++'and sc.sid=student.sid and sc.cid=course.cid) a, (select student.SNAME,student.SID from student,course,sc where cname='english'and sc.sid=student.sid and sc.cid=course.cid) b where a.sid=b.sid; 标准答案(但是好像不好使)SELECT Student.S SC.C 此题知识点,exists是在集合里找数据,as就是起别名
7.查询学过“叶平”老师所教的所有课的同学的学号、姓名; select a.sid,a.sname from (select student.sid,student.sname from student,teacher,course,sc where teacher.TNAME='杨巍巍' and teacher.tid=course.tid and course.cid=sc.cid and student.sid=sc.sid) a 标准答案:SELECT sid,Sname FROM Student WHERE sid in (SELECT sid FROM SC ,Course ,Teacher WHERE SC.cid=Course.cid AND Teacher.tid=Course.tid AND Teacher.Tname='杨巍巍' GROUP BY sid having count(SC.cid)=(SELECT count(cid) FROM Course,Teacher WHERE Teacher.tid=Course.tid AND Tname='杨巍巍'))
8.查询课程编号“”的成绩比课程编号“”课程低的所有同学的学号、姓名; select a.sid,a.sname from(select student.SID,student.sname,sc.SCORE from student,sc where student.sid=sc.sid and sc.cid=1) a, (select student.SID,student.sname,sc.score from student,sc where student.sid=sc.sid and sc.cid=2) b where a.score<b.score and a.sid=b.sid 标准答案:SELECT sid,Sname FROM (SELECT Student.sid,Student.Sname,score , (SELECT score FROM SC SC_2 WHERE SC_2.sid=Student.sid AND SC_2.cid=1) score2 FROM Student,SC WHERE Student.sid=SC.sid AND cid=1) S_2 WHERE score2 <score;
9.查询所有课程成绩小于分的同学的学号、姓名; SELECT sid,Sname FROM Student WHERE sid not in (SELECT Student.sid FROM Student,SC WHERE Student.sid=SC.sid AND score>60); 此题知识点,先查出大于60分的,然后not in 就是小于60分的了
10.查询没有学全所有课的同学的学号、姓名; SELECT Student.sid,Student.Sname FROM Student,SC WHERE Student.sid=SC.sid GROUP BY Student.sid,Student.Sname having count(cid) <(SELECT count(cid) FROM Course);
11.查询至少学过学号为“”同学所有一门课的其他同学学号和姓名; SELECT student.sid,student.Sname FROM Student,SC WHERE Student.sid=SC.sid AND cid in (SELECT cid FROM SC WHERE sid=1) 此题知识点, SELECT sid,Sname FROM Student,SC WHERE Student.sid=SC.sid AND cid in (SELECT cid FROM SC WHERE sid=1) 这样写是错误的,因为from后面是两个表,不能明确是哪个表里面的sid和sname所以错误提示是“未明确定义列”
12.把“SC”表中“叶平”老师教的课的成绩都更改为此课程的平均成绩; update sc set score=(select avg(score) from sc,course,teacher where course.cid=sc.cid and course.tid=teacher.tid and teacher.tname='杨巍巍')
13.查询和“”号的同学学习的课程完全相同的其他同学学号和姓名; SELECT sid FROM SC WHERE cid in (SELECT cid FROM SC WHERE sid=6) GROUP BY sid having count(*)=(SELECT count(*) FROM SC WHERE sid=6); 此题知识点,用数量来判断
14.删除学习“叶平”老师课的SC表记录; delete from sc s where s.cid in (select c.cid from teacher t,course c where t.tid = c.tid and tname='李子') 此题知识点,嵌套查询可以分布考虑,先查出李子老师都交了什么课的id,然后再删除那些id的值
15.向SC表中插入一些记录,这些记录要求符合以下条件:没有上过编号“”课程的同学学号、课程的平均成绩; Insert into SC SELECT sid,2,(SELECT avg(score) FROM SC WHERE cid=2) FROM Student WHERE sid not in (SELECT sid FROM SC WHERE cid=2);
16.查询各科成绩最高和最低的分:以如下形式显示:课程ID,最高分,最低分; select cid as 课程号,max(score)as 最高分,min(score) as 最低分 from sc group by cid 标准答案(但是运行不好使)SELECT L.cid As 课程ID,L.score AS 最高分,R.score AS 最低分 FROM SC L ,SC AS R WHERE L.cid = R.cid AND L.score = (SELECT MAX(IL.score) FROM SC AS IL,Student AS IM WHERE L.cid = IL.cid AND IM.sid=IL.sid GROUP BY IL.cid) AND R.Score = (SELECT MIN(IR.score) FROM SC AS IR WHERE R.cid = IR.cid GROUP BY IR.cid );
17.查询每门课程被选修的学生数 select sc.cid,count(sc.sid) from sc,course where sc.cid=course.cid group by sc.cid
18.查询出只选修了一门课程的全部学生的学号和姓名 SELECT SC.sid,Student.Sname,count(cid) AS 选课数 FROM SC ,Student WHERE SC.sid=Student.sid GROUP BY SC.sid ,Student.Sname having count(cid)=1;
19.查询每门课程的平均成绩,结果按平均成绩升序排列,平均成绩相同时,按课程号降序排列 SELECT Cid,Avg(score) FROM SC GROUP BY cid ORDER BY Avg(score),cid DESC ;
20.查询不及格的课程,并按课程号从大到小排列 SELECT cid,sid FROM sc WHERE score <60 ORDER BY cid
21.查询课程编号为且课程成绩在分以上的学生的学号和姓名; select student.sid,student.sname from sc,student where sc.cid=1 and sc.score>60 and sc.sid=student.sid
22.查询选修“叶平”老师所授课程的学生中,成绩最高的学生姓名及其成绩 select student.sname,sc.score from sc,student,teacher,course c where teacher.tname='叶平' and teacher.tid=c.tid and c.cid=sc.cid and sc.sid=student.sid and sc.score=(select max(score)from sc where sc.cid=c.cid)
23.查询各个课程及相应的选修人数 select sc.cid ,count(sc.sid)from sc,student where sc.sid=student.sid group by sc.cid
24.统计每门课程的学生选修人数(超过人的课程才统计)。要求输出课程号和选修人数,查询结果按人数降序排列,查询结果按人数降序排列,若人数相同,按课程号升序排列 select sc.cid,count(sc.cid)from sc,course where sc.cid=course.cid group by sc.cid order by sc.cid desc
25.检索至少选修两门课程的学生学号 SELECT sid FROM sc group by sid having count(*) > = 2 rownum的用法 查询所有成绩第二名到第四名的成绩 select * from (select rownum p,t.score from(SELECT s.score score FROM sc s ORDER BY score desc)t )tt where tt.p>1 and tt.p<5
26.查询没学过“叶平”老师讲授的任一门课程的学生姓名 select distinct sid from sc where sid not in(select sc.sid from sc,course,teacher where sc.cid=course.cid and course.tid=teacher.tid and teacher.tname='叶平')
27.检索“ ”课程分数小于90,按分数降序排列的同学学号 select sc.sid from sc,course where sc.cid=course.cid and course.cname='java' and sc.score<90
28.删除“ ”同学的“ ”课程的成绩 delete from sc where sid=1 and cid=1
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