We define the Perfect Number is a positive integer that is equal to the sum of all its positive divisors except itself.
Now, given an integer n, write a function that returns true when it is a perfect number and false when it is not.
Example:
Input: 28 Output: True Explanation: 28 = 1 + 2 + 4 + 7 + 14
Note: The input number n will not exceed 100,000,000. (1e8)
分析¶
完全数的所有的真因子(即除了自身以外的约数)的和,恰好等于它本身。时间复杂度O(log n)。
public boolean checkPerfectNumber(int num) { if (num < 2) return false; // 1 肯定是因子 int sum = 1; for (int i = 2; i * i < num; i++) { // i从2开始 if (num % i == 0) sum += i + num/i; } return sum == num; }





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