binary tree zigzag level order traversal


Given a binary tree, return the zigzag level order traversal of its nodes’ values. (ie, from left to right, then right to left for the next level and alternate between).

For example:
Given binary tree [3,9,20,null,null,15,7],

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2
3
4
5
3
/
9 20
/
15 7

return its zigzag level order traversal as:

1
2
3
4
5
[
[3],
[20,9],
[15,7]
]

Solution

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* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class {
public List<List<Integer>> zigzagLevelOrder(TreeNode root) {
List<List<Integer>> res = new ArrayList<List<Integer>>();
LinkedList<TreeNode> queue = new LinkedList<TreeNode>();
if(root==null) return res;
queue.offer(root);
boolean change = true;
while(!queue.isEmpty()){
int size = queue.size();
List<Integer> sub = new ArrayList<Integer>();
for(int i=0;i<size;i++){
TreeNode node = queue.poll();
if(change) {
sub.add(node.val);
} else {
sub.add(0,node.val);
}
if(node.left!=null) queue.offer(node.left);
if(node.right!=null) queue.offer(node.right);
}
res.add(sub);
change = !change;
}
return res;
}
}