
Given a collection of intervals, merge all overlapping intervals.
For example,
Given [1,3],[2,6],[8,10],[15,18],
return [1,6],[8,10],[15,18].
Solution
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* Definition for an interval. * public class Interval { * int start; * int end; * Interval() { start = 0; end = 0; } * Interval(int s, int e) { start = s; end = e; } * } */ public class { public List<Interval> merge(List<Interval> intervals) { if(intervals.size()<=1) return intervals; intervals.sort((o1,o2)->Integer.compare(o1.start,o2.start)); int start = intervals.get(0).start; int end = intervals.get(0).end; List<Interval> res = new ArrayList<Interval>(); for(int i=0; i<intervals.size();i++) { if(intervals.get(i).start <= end) { end = Math.max(end,intervals.get(i).end); } else { res.add(new Interval(start,end)); start = intervals.get(i).start; end = intervals.get(i).end; } } res.add(new Interval(start,end)); return res; } }
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