Path Sum


Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:

Given the below binary tree and sum = 2

1
2
3
4
5
6
7
5
/
4 8
/ /
11 13 4
/
7 2 1

return true, as there exist a root-to-leaf path 5->4->11->2 which sum is 22.


My Solution:

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* Definition for a binary tree node.
* public class TreeNode {
* int val;
* TreeNode left;
* TreeNode right;
* TreeNode(int x) { val = x; }
* }
*/
public class {
public boolean hasPathSum(TreeNode root, int sum) {
if (root == null) return false;
if (root.left == null && root.right == null)
return sum == root.val;
return hasPathSum(root.left, sum-root.val) || hasPathSum(root.right,sum-root.val);
}
}

递归思想