Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.
For example:
Given the below binary tree and sum = 2
1 2 3 4 5 6 7
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5 / 4 8 / / 11 13 4 / 7 2 1
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return true, as there exist a root-to-leaf path 5->4->11->2
which sum is 22.
My Solution:
1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17
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* Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class { public boolean hasPathSum(TreeNode root, int sum) { if (root == null) return false; if (root.left == null && root.right == null) return sum == root.val; return hasPathSum(root.left, sum-root.val) || hasPathSum(root.right,sum-root.val); } }
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递归思想
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