Given an integer array nums, return the number of range sums that lie in [lower, upper] inclusive. Range sum S(i, j) is defined as the sum of the elements in nums between indices i and j (i ≤ j), inclusive.
Note:
A naive algorithm of O(n2) is trivial. You MUST do better than that.
Example:
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Input: nums = [-2,5,-1], lower = -2, upper = 2, Output: 3 Explanation: The three ranges are : [0,0], [2,2], [0,2] and their respective sums are: -2, -1, 2.
Solution
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class { public: intcountRangeSum(std::vector<int>& nums, int lower, int upper){ auto sums = std::multiset<longlong>(); int res = 0; sums.insert(0); longlong sum = 0; for(auto num : nums) { sum += num; res += std::distance(sums.lower_bound(sum - upper), sums.upper_bound(sum - lower)); sums.insert(sum); } return res; } };
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